Coordinate Plane Geometry
Quick Recap for Aspirants (40 MCQs) | Brought to you by NRCODEAI
CO-ORDINATE PLANE GEOMETRY
Introduction
Coordinate geometry (or analytical geometry) is the bridge between algebra and geometry. It involves studying geometry using a coordinate system, allowing geometric shapes to be defined by algebraic equations.
Brief Overview
1. The Cartesian Plane
- Axes: The horizontal line is the x-axis, and the vertical line is the y-axis.
- Origin: The point where the axes intersect, denoted as $(0, 0)$.
- Quadrants: The axes divide the plane into four quadrants (I, II, III, IV), moving counter-clockwise.
- Quadrant I: $(+, +)$
- Quadrant II: $(-, +)$
- Quadrant III: $(-, -)$
- Quadrant IV: $(+, -)$
- Coordinates: Any point is defined by an ordered pair $(x, y)$, where $x$ is the abscissa (horizontal distance) and $y$ is the ordinate (vertical distance).
Numerical Example:
Plot the point $(-3, 4)$.
Start at the origin $(0,0)$. Move 3 units to the left along the x-axis, then move 4 units up parallel to the y-axis. The point lies in Quadrant II.
MCQs - The Cartesian Plane
- The vertical axis on a coordinate plane is called the:
a) x-axis
b) y-axis
c) Origin
d) Z-axis
Answer: b - The coordinates of the origin are:
a) $(1, 1)$
b) $(0, 1)$
c) $(1, 0)$
d) $(0, 0)$
Answer: d - In which quadrant does the point $(-2, -5)$ lie?
a) Quadrant I
b) Quadrant II
c) Quadrant III
d) Quadrant IV
Answer: c - The x-coordinate of a point is also known as its:
a) Ordinate
b) Abscissa
c) Origin
d) Intercept
Answer: b - A point of the form $(x, 0)$ always lies on the:
a) x-axis
b) y-axis
c) Origin
d) Cannot be determined
Answer: a - If a point lies on the y-axis, its x-coordinate is:
a) 1
b) -1
c) 0
d) Undefined
Answer: c - The point $(4, -3)$ is located in which quadrant?
a) Quadrant I
b) Quadrant II
c) Quadrant III
d) Quadrant IV
Answer: d - What is the perpendicular distance of the point $(5, 7)$ from the x-axis?
a) 5
b) 7
c) 12
d) 2
Answer: b - The axes in the Cartesian coordinate system are:
a) Parallel to each other
b) Perpendicular to each other
c) Coincident
d) At a 45-degree angle
Answer: b - Which of the following points lies in Quadrant II?
a) $(3, 5)$
b) $(-3, 5)$
c) $(-3, -5)$
d) $(3, -5)$
Answer: b
2. Distance Formula
- Used to find the exact distance between two points $P(x_1, y_1)$ and $Q(x_2, y_2)$ on the coordinate plane.
- Derived directly from the Pythagorean theorem.
- Formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Numerical Example:
Find the distance between $(1, 2)$ and $(4, 6)$.
$x_1=1, y_1=2, x_2=4, y_2=6$.
$d = \sqrt{(4 - 1)^2 + (6 - 2)^2}$
$d = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5$.
The distance is 5 units.
MCQs - Distance Formula
- The distance formula is derived from:
a) Area of a circle
b) Quadratic formula
c) Pythagorean theorem
d) Euler's formula
Answer: c - What is the distance between the origin $(0,0)$ and the point $(3, 4)$?
a) 3
b) 4
c) 5
d) 7
Answer: c - Find the distance between $(0, 5)$ and $(0, -2)$.
a) 3
b) -7
c) 7
d) 10
Answer: c (Vertical line: $|5 - (-2)| = 7$) - The distance between $(x_1, y_1)$ and the origin is given by:
a) $\sqrt{x_1 + y_1}$
b) $\sqrt{x_1^2 + y_1^2}$
c) $x_1^2 + y_1^2$
d) $|x_1 - y_1|$
Answer: b - Calculate the squared distance ($d^2$) between $(1, 1)$ and $(2, 2)$.
a) 1
b) 2
c) 4
d) $\sqrt{2}$
Answer: b ($ (2-1)^2 + (2-1)^2 = 1 + 1 = 2 $) - What is the distance between the points $(a, b)$ and $(-a, -b)$?
a) $2\sqrt{a^2 + b^2}$
b) $\sqrt{a^2 + b^2}$
c) $4(a^2 + b^2)$
d) $0$
Answer: a - If the distance between points $(2, 3)$ and $(5, y)$ is 5, a possible value for y is:
a) -1
b) 1
c) 7
d) Both a and c
Answer: d (Since $(5-2)^2 + (y-3)^2 = 25 \implies 9 + (y-3)^2 = 25 \implies (y-3)^2 = 16 \implies y-3 = \pm 4 \implies y = 7, -1$) - The distance between a point $P(x, y)$ and the origin is 10. Which of these could be the coordinates of P?
a) $(5, 5)$
b) $(6, 8)$
c) $(7, 3)$
d) $(10, 10)$
Answer: b - Find the perimeter of a triangle with vertices $(0,0)$, $(3,0)$, and $(0,4)$.
a) 12
b) 10
c) 7
d) 5
Answer: a ($3 + 4 + \sqrt{3^2+4^2} = 3+4+5=12$) - The distance between the points $(\cos \theta, \sin \theta)$ and $(-\sin \theta, \cos \theta)$ is:
a) 1
b) 2
c) $\sqrt{2}$
d) 0
Answer: c
3. Section Formula and Midpoint Formula
- Section Formula: Finds the coordinates of a point $P(x, y)$ that divides a line segment connecting $A(x_1, y_1)$ and $B(x_2, y_2)$ internally in the ratio $m:n$.
- $x = \frac{mx_2 + nx_1}{m + n}$
- $y = \frac{my_2 + ny_1}{m + n}$
- Midpoint Formula: A special case of the section formula where the ratio is $1:1$ (the exact middle).
- $M = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$
Numerical Example:
Find the midpoint of the line segment joining $(-2, 4)$ and $(6, 8)$.
$x = \frac{-2 + 6}{2} = \frac{4}{2} = 2$.
$y = \frac{4 + 8}{2} = \frac{12}{2} = 6$.
The midpoint is $(2, 6)$.
MCQs - Midpoint and Section Formulas
- The formula used to find the exact center of a line segment is the:
a) Distance formula
b) Midpoint formula
c) Section formula
d) Area formula
Answer: b - Find the midpoint of the segment joining $(0, 0)$ and $(10, 10)$.
a) $(10, 0)$
b) $(0, 10)$
c) $(5, 5)$
d) $(20, 20)$
Answer: c - In the section formula, if a point divides a segment internally in the ratio $m:n$, the denominator is always:
a) $m - n$
b) $m \times n$
c) $m + n$
d) $m / n$
Answer: c - What is the midpoint of $(x, y)$ and $(-x, -y)$?
a) $(2x, 2y)$
b) $(x^2, y^2)$
c) $(0, 0)$
d) $(1, 1)$
Answer: c (The origin) - A point divides the line joining $(0,0)$ and $(3,0)$ in the ratio $1:2$. What is its x-coordinate?
a) 1
b) 2
c) 1.5
d) 3
Answer: a ($ x = \frac{1(3) + 2(0)}{1+2} = 3/3 = 1 $) - The midpoint of a line segment is $(3, 4)$ and one endpoint is $(1, 2)$. What is the other endpoint?
a) $(2, 3)$
b) $(5, 6)$
c) $(4, 6)$
d) $(2, 2)$
Answer: b (Because $\frac{1+x}{2}=3 \implies x=5$ and $\frac{2+y}{2}=4 \implies y=6$) - In what ratio does the y-axis divide the line segment joining the points $(-3, -4)$ and $(1, -2)$?
a) $3:1$
b) $1:3$
c) $2:1$
d) $1:2$
Answer: a (The x-coordinate is 0, so $\frac{k(1) + 1(-3)}{k+1} = 0 \implies k=3$) - The centroid of a triangle with vertices $(x_1, y_1)$, $(x_2, y_2)$, and $(x_3, y_3)$ is:
a) $(\frac{x_1+x_2+x_3}{2}, \frac{y_1+y_2+y_3}{2})$
b) $(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3})$
c) $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
d) $(\frac{x_1-x_2-x_3}{3}, \frac{y_1-y_2-y_3}{3})$
Answer: b - A line segment joining $(2, 3)$ and $(6, 7)$ is divided into four equal parts. Which of these points is NOT one of the division points?
a) $(3, 4)$
b) $(4, 5)$
c) $(5, 6)$
d) $(4, 4)$
Answer: d - If the origin is the midpoint of the line segment joined by $(a, -b)$ and $(c, d)$, then:
a) $a = c$, $b = d$
b) $a = -c$, $b = d$
c) $a = c$, $b = -d$
d) $a = -c$, $b = -d$
Answer: b (Since $\frac{a+c}{2} = 0 \implies a = -c$ and $\frac{-b+d}{2} = 0 \implies b = d$)
4. Area of a Triangle using Coordinates
- If the vertices of a triangle are $A(x_1, y_1)$, $B(x_2, y_2)$, and $C(x_3, y_3)$, the area of the triangle can be calculated without knowing its base or height.
- Formula: $\text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$
- If the area calculates to exactly 0, it means the three points are collinear (they form a straight line, not a triangle).
Numerical Example:
Find the area of a triangle with vertices $(0, 0)$, $(4, 0)$, and $(0, 3)$.
Area $= \frac{1}{2} |0(0 - 3) + 4(3 - 0) + 0(0 - 0)|$
$= \frac{1}{2} |0 + 12 + 0| = \frac{1}{2} \times 12 = 6$ square units.
MCQs - Area of a Triangle
- If the area of a triangle formed by three points is zero, the points are:
a) Concyclic
b) Collinear
c) Coplanar
d) Equilateral
Answer: b - Find the area of a triangle with vertices $(0,0)$, $(5,0)$, and $(0,4)$.
a) 20
b) 10
c) 9
d) 4.5
Answer: b ($\frac{1}{2} \times 5 \times 4 = 10$) - The formula for the area of a coordinate triangle uses absolute value brackets because:
a) Area cannot be negative
b) Coordinates cannot be negative
c) Triangles have three sides
d) It is an approximation
Answer: a - A triangle has vertices at the origin and on the positive x and y axes. What type of triangle is it?
a) Equilateral
b) Isosceles
c) Right-angled
d) Obtuse
Answer: c (The axes are perpendicular) - The area of a triangle formed by $(x_1, y_1)$, $(x_2, y_2)$, and $(x_3, y_3)$ is half the value of a certain determinant.
a) True
b) False
Answer: a (The formula is derived from a determinant) - What is the area of the triangle formed by the points $(0,0)$, $(a,0)$, and $(0,b)$?
a) $ab$
b) $a+b$
c) $\frac{1}{2} ab$
d) $\frac{1}{2} (a+b)$
Answer: c - If three points $A, B,$ and $C$ are collinear, then the area of $\Delta ABC$ is:
a) 1
b) 0
c) $-1$
d) Infinite
Answer: b - Find the area of the triangle with vertices $(1, 2)$, $(3, 4)$, and $(5, 2)$.
a) 4
b) 8
c) 2
d) 6
Answer: a (Area = $\frac{1}{2}|1(4-2) + 3(2-2) + 5(2-4)| = \frac{1}{2}|2 + 0 - 10| = 4$) - The area of a quadrilateral can be found by:
a) Using the midpoint formula
b) Dividing it into two triangles and summing their areas
c) Multiplying the diagonals
d) Finding the perimeter
Answer: b - Which points form a triangle of area 0?
a) $(1,1), (2,2), (3,3)$
b) $(1,0), (0,1), (1,1)$
c) $(0,0), (4,0), (0,5)$
d) $(-1,-1), (2,3), (-2,-3)$
Answer: a (They lie on the line $y=x$)
Fun Facts about Coordinate Geometry!
- Fly on the Ceiling: The legend goes that René Descartes invented the coordinate system while lying in bed, watching a fly crawl on the ceiling, and realizing he could describe its position using its distance from the two adjacent walls!
- Cartesian: The system is named "Cartesian" in honor of Descartes (whose Latinized name was Cartesius).
- GPS Base: Without coordinate geometry, GPS navigation would be impossible! Satellites use advanced 3D coordinate geometry to pinpoint exactly where you are on Earth.
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